Question

Sin(arccos√3/2+arcsin(-1/2))

Answer 1

arccos(√3/2) = π/6,

arcsin(-1/2) = -π/6,

sin(arccos√3/2+arcsin(-1/2)) = sin( π/6 - π/6) = sin(0) = 0.

Ответ. 0.

Answer 2

Let's break down the expression step by step:

1. arccos(√3/2) is the angle whose cosine is √3/2. This corresponds to π/6 radians or 30 degrees.
2. arcsin(-1/2) is the angle whose sine is -1/2. This corresponds to -π/6 radians or -30 degrees.

Now, we'll add these angles together:

arccos(√3/2) + arcsin(-1/2) = π/6 - π/6 = 0

So, the expression simplifies to:

sin(0) = 0

Therefore, Sin(arccos(√3/2) + arcsin(-1/2)) equals 0.