Question

8x^2 - 2x ( 4x+1) ≥ x

Answer 1

Ответ: x

8x^2-2x(4x+1) ≥x

8x^2-8x^2-2x ≥x

-2x ≥x

0 ≥-3x

Пошаговое объяснение:

Answer 2

Ответ:

8x^2-8x^2-2x-x≥0

-3x≥0

x⩽0

Пошаговое объяснение:

Answer 3

To solve the inequality 8x^2 - 2x(4x + 1) ≥ x, let's simplify and rearrange the terms:

8x^2 - 8x^2 - 2x ≥ x - 0

Simplifying further:

-2x ≥ x

To solve for x, we need to isolate x on one side of the inequality. Let's move -2x to the right side by adding 2x to both sides:

-2x + 2x ≥ x + 2x

0 ≥ 3x

Since 0 is greater than or equal to any negative number, the inequality holds for all values of x. Therefore, the solution to the inequality is:

x ∈ (-∞, +∞) or (-infinity, positive infinity)