Question

(1/4)y+3=21-(1/12)y -7x-32=6x+46

Answer 1

Ответ:

y=54 и x= -6

Пошаговое объяснение:

(1/4)y+(1/12)y=21-3(переносим с переменной в одну часть и с числами в другую)

(3/12)y+(1/12)y=18

(4/12)y=18

y=18/(4/12), переворачиваем дробь и меняем деление на умножение

y=18*12/4

y=54

-7x-6x=46+32(переносим с переменной в одну часть и с числами в другую)

-13x=78

x=78/(-13)

x= -6

Answer 2

It seems like you have two separate equations that you'd like to solve for their respective variables. Let's solve each equation step by step.

Equation 1: (1/4)y + 3 = 21 - (1/12)y

To solve for y, we want to isolate y on one side of the equation. We can start by adding (1/12)y to both sides to get rid of the y term on the right side:

(1/4)y + (1/12)y + 3 = 21

Now, we need to find a common denominator for (1/4) and (1/12), which is 12. Let's convert the fractions:

(3/12)y + (1/12)y + 3 = 21

Combining the y terms:

(4/12)y + 3 = 21

Simplify the left side:

(1/3)y + 3 = 21

Now, subtract 3 from both sides:

(1/3)y = 18

Multiply both sides by 3 to solve for y:

y = 18 * 3 y = 54

So, the solution for the first equation is y = 54.

Equation 2: -7x - 32 = 6x + 46

To solve for x, we can start by moving all the x terms to one side of the equation and the constants to the other side:

-7x - 6x = 46 + 32

-13x = 78

Now, divide both sides by -13 to solve for x:

x = 78 / -13 x = -6

The solution for the second equation is x = -6.

So, the solutions are y = 54 and x = -6 for the respective equations.