Question

4) (8x – 3y - 7 = 0,3x + y - 9 = 0;​

Answer 1

{8x-3y=7
{3x+y=9 |•3
{8x-3y=7
{9x+3y=27
{17x=34
x=2
8•2-3y=7
-3y=-9
y=3

Answer 2

It looks like you've provided a system of two equations with two variables:

Equation 1: $8x - 3y - 7 = 0$ Equation 2: $3x + y - 9 = 0$

You can solve this system of equations using various methods such as substitution, elimination, or matrix methods. Let's solve it using the substitution method:

Step 1: Solve one of the equations for one variable. Let's solve Equation 2 for $y$: $3x + y - 9 = 0$ $y = 9 - 3x$

Step 2: Substitute the expression for $y$ into the other equation. Substitute $y = 9 - 3x$ into Equation 1: $8x - 3(9 - 3x) - 7 = 0$ $8x - 27 + 9x - 7 = 0$ $17x - 34 = 0$ $17x = 34$ $x = 2$

Step 3: Substitute the value of $x$ into the equation for $y$: $y = 9 - 3x$ $y = 9 - 3(2)$ $y = 9 - 6$ $y = 3$

So, the solution to the system of equations is $x = 2$ and $y = 3$. The point of intersection for these two equations is (2, 3). This is the unique solution to the given system of equations.