Question

5(2х—3у)+х+4у=11 2) (2х+5у)—х+9у=3 у​

Answer 1

Ответ:

Пж прощуууу на спасибо нажми

Пошаговое объяснение:

Answer 2

It looks like you have a system of two equations with two variables:

1. $5(2x - 3y) + x + 4y = 11$
2. $2x + 5y - x + 9y = 3$

Let's solve this system of equations step by step.

Equation 1: $5(2x - 3y) + x + 4y = 11$ Distribute the 5 on the left side: $10x - 15y + x + 4y = 11$

Combine like terms: $11x - 11y = 11$

Divide both sides by 11: $x - y = 1$

Equation 2: $2x + 5y - x + 9y = 3$ Combine like terms: $x + 14y = 3$

Now you have a simplified system of equations:

1. $x - y = 1$
2. $x + 14y = 3$

You can solve this system using either the substitution method or the elimination method. Let's use the substitution method.

From equation 1, solve for $x$: $x = y + 1$

Now substitute the value of $x$ into equation 2: $y + 1 + 14y = 3$

Combine like terms: $15y + 1 = 3$

Subtract 1 from both sides: $15y = 2$

Divide both sides by 15: $y = \frac{2}{15}$

Now that you have the value of $y$, you can substitute it back into the equation for $x$: $x = y + 1 = \frac{2}{15} + 1 = \frac{17}{15}$

So, the solution to the system of equations is $x = \frac{17}{15}$ and $y = \frac{2}{15}$.