Question

213*(x-89)=9585. 4848:(60-x)=101 (x+51)*309=16686 9435:(77-x)=555

Answer 1

Пошаговое объяснение: №1.

213*(x-89)=9585

213х-18957=9585

213х=9585+18957

213х=28542

х=28542:213

х=134

№2.

4848:(60-x)=101

60-х=4848:101

60-х=48

х=60-48

х=12

№3.

(x+51)*309=16686

х+51=16686:309

х+51=54

х=54-51

х=3

№4.

9435:(77-x)=555

77-х=9435:555

77-х=17

х=77-17

х=60

Answer 2

It looks like you've provided a system of equations with multiple variables. You're looking to solve for the values of 'x' that satisfy each equation. Let's solve them one by one:

1. $213 \cdot (x - 89) = 9585$

First, distribute the 213 on the left side of the equation:

$213x - 213 \cdot 89 = 9585$

Now, simplify:

$213x - 18957 = 9585$

Add 18957 to both sides:

$213x = 28542$

Finally, divide both sides by 213:

$x = \frac{28542}{213} \approx 134$

2. $4848:(60 - x) = 101$

We can rewrite this equation as a multiplication by the reciprocal:

$4848 \cdot \frac{1}{60 - x} = 101$

Now, isolate the fraction:

$\frac{4848}{101} = 60 - x$

Subtract $\frac{4848}{101}$ from both sides:

$60 - \frac{4848}{101} = x$

$x \approx 10.376$

3. $(x + 51) \cdot 309 = 16686$

Distribute the 309 on the left side of the equation:

$309x + 309 \cdot 51 = 16686$

Now, simplify:

$309x + 15759 = 16686$

Subtract 15759 from both sides:

$309x = 927$

Divide both sides by 309:

$x = \frac{927}{309} \approx 3$

4. $9435:(77 - x) = 555$

Similar to the second equation, rewrite it as a multiplication by the reciprocal:

$9435 \cdot \frac{1}{77 - x} = 555$

Isolate the fraction:

$\frac{9435}{555} = 77 - x$

Subtract $\frac{9435}{555}$ from both sides:

$77 - \frac{9435}{555} = x$

$x \approx -3.59$

So, the solutions for the equations are approximately:

1. $x \approx 134$
2. $x \approx 10.376$
3. $x \approx 3$
4. $x \approx -3.59$