Question

(1550+1551+1552+,,,,,+1648+1649)-(150+151+152+,,,,+248+249)​

Answer 1

Ответ:

ровно 7000 но зачем эти ,,,,,,

Answer 2

To calculate the given expression, you need to find the sum of the numbers from 1550 to 1649, and subtract the sum of the numbers from 150 to 249.

The sum of consecutive numbers can be found using the formula for the sum of an arithmetic series:

Sn = (n/2) * (a + l)

Where: Sn is the sum of the series n is the number of terms a is the first term l is the last term

First, let's calculate the sum of the numbers from 1550 to 1649:

n = (1649 - 1550) + 1 = 100 (number of terms) a = 1550 (first term) l = 1649 (last term)

Sum1 = (100/2) * (1550 + 1649) = 50 * (3199) = 159950

Next, let's calculate the sum of the numbers from 150 to 249:

n = (249 - 150) + 1 = 100 (number of terms) a = 150 (first term) l = 249 (last term)

Sum2 = (100/2) * (150 + 249) = 50 * (399) = 19950

Finally, subtract Sum2 from Sum1 to get the result:

Result = Sum1 - Sum2 = 159950 - 19950 = 140000

Therefore, the value of the expression (1550+1551+1552+...+1648+1649)-(150+151+152+...+248+249) is 140,000.