Question

1) 205:(y-27)=41 2) (200+x):12=32 3) 82z-57z=575

Answer 1

Ответ:

1)32

2)184

3)23

Пошаговое объяснение:

1)205:41=у-27

5=у-27

у=32

2)200+х=32*12

200+х=384

х=184

3)25z=575

z=23

Answer 2

It looks like you've provided three mathematical equations. Let's solve each of them step by step:

1. $205 \cdot (y - 27) = 41$

First, distribute the 205 on the left side:

$205y - 205 \cdot 27 = 41$

Simplify:

$205y - 5535 = 41$

Now, isolate $y$ by adding 5535 to both sides:

$205y = 5576$

Finally, divide both sides by 205:

$y = \frac{5576}{205}$

This can be further simplified if needed.

2. $\frac{200 + x}{12} = 32$

Multiply both sides by 12 to eliminate the fraction:

$200 + x = 32 \cdot 12$

$200 + x = 384$

Subtract 200 from both sides:

$x = 384 - 200$

$x = 184$

3. $82z - 57z = 575$

Simply subtract the left side:

$25z = 575$

Now, divide both sides by 25:

$z = \frac{575}{25}$

$z = 23$

So, the solutions are:

1. $y = \frac{5576}{205}$
2. $x = 184$
3. $z = 23$