Question

141. 1) 502 саны 22 088 санының 2) 65 667 саны 3127 санының еселігі;3) 13 188 саны 24 санының еселігі;4) 762 саны 16664 санының бөлгіші;5) 93 саны 9579 санының бөлгіші;6) 25 400 саны 154 санының еселігі;7) 5372 саны 68 санының еселігі;8) 911 саны 4555 санының бөлгіші болатыны дұрыс142. 1) 7 <a < 27; 2) 50 < x < 83;3) 305 <b< 330; 4) 918 < у < 955теңсіздіктерін қанағаттандыратын барлық жай сандар143. 1) 24-тің бөлгіші және 6-ға еселік;2) 36-ның бөлгіші және 9-ға еселік;3) 100-дің бөлгіші және 20-ға еселік;4) 108-дің бөлгіші және 36-ға еселік болатын санда​

Answer 1

Ответ:

) 22088 : 502 = 44 - да;

2) 65667 : 3127 = 21 - да;

3) 13188 : 24 = 549 (ост. 12) - нет;

4) 16664 : 762 = 21 (ост. 662) - нет;

5) 9579 : 93 = 103 - да;

6) 25400 : 154 = 164 (ост. 144) - нет;

7) 5372 : 68 = 79 - да;

8) 4555 : 911 = 5 - да.

Answer 2

141. Here are the calculations:

1. The remainder of dividing 502 by 22,088 is 502.
2. The remainder of dividing 65,667 by 3,127 is 55.
3. The remainder of dividing 13,188 by 24 is 12.
4. The quotient of dividing 762 by 16,664 is 0 (with a remainder of 762).
5. The quotient of dividing 93 by 9,579 is 0 (with a remainder of 93).
6. The remainder of dividing 25,400 by 154 is 86.
7. The remainder of dividing 5,372 by 68 is 52.
8. The quotient of dividing 911 by 4,555 is 0 (with a remainder of 911).

142. Here are the inequalities that satisfy the given conditions:

1. 7 < a < 27
2. 50 < x < 83
3. 305 < b < 330
4. 918 < y < 955

These inequalities represent the range of values that satisfy the conditions.

143. Here are the calculations:

1. The quotient of dividing 24 by 6 is 4, and the remainder of dividing 24 by 6 is 0.
2. The quotient of dividing 36 by 9 is 4, and the remainder of dividing 36 by 9 is 0.
3. The quotient of dividing 100 by 20 is 5, and the remainder of dividing 100 by 20 is 0.
4. The quotient of dividing 108 by 36 is 3, and the remainder of dividing 108 by 36 is 0.

In each case, the quotient is a whole number and the remainder is zero, indicating that the given numbers are divisible by the divisor without any remainder.