Question

6tg2 x + tg x -1 = 0​

Answer 1

Ответ:

х=3. ок осылай шыгады ♥️♥️♥️

х=6

Пошаговое объяснение:

Рахмет сізге

Answer 2

The equation you provided is a trigonometric equation. Let's solve it.

The given equation is: 6tg^2(x) + tg(x) - 1 = 0

To simplify the equation, let's replace tg(x) with its equivalent form in terms of sine and cosine. We know that tg(x) = sin(x) / cos(x). So, we can rewrite the equation as:

6(sin^2(x) / cos^2(x)) + (sin(x) / cos(x)) - 1 = 0

Multiplying the entire equation by cos^2(x) to eliminate the denominators, we get:

6sin^2(x) + sin(x)cos(x) - cos^2(x) = 0

Now, let's rewrite sin(x)cos(x) as (1/2)sin(2x) using the double-angle formula:

6sin^2(x) + (1/2)sin(2x) - cos^2(x) = 0

Using the trigonometric identity sin^2(x) + cos^2(x) = 1, we can replace cos^2(x) with 1 - sin^2(x):

6sin^2(x) + (1/2)sin(2x) - (1 - sin^2(x)) = 0

Rearranging the terms, we get:

7sin^2(x) + (1/2)sin(2x) - 1 = 0

This equation can now be solved using standard algebraic techniques or numerical methods. However, finding an exact solution may not be possible without more information or restrictions on the range of x.

If you have any additional constraints or specific values for x, please let me know so I can assist you further.