Question

1)77-(45+x)=13. 2)(30-x)+21=42 3) 34+(x-23)=69. 4)(156x)-61=72 5)324-(x+52)=223.

Answer 1

Ответ:

1) 77-45-х=13

-х=13-77+45

-х=-19

х=19

2) -х= 42-30-21

-х= -9

х=9

3) х=69-34+23

х=58

4) 156х=61+72

156х=133

х=133/156

5) х= 223-324+52

х= -49

Answer 2

Ответ:

1) 77-(45+x)=13

77-45-x=13

32-x=13

-x=13-32

-x=-19

X=19

2)(30-x)+21=42

30-x+21=42

51-x=42

-x=42-51

-x=-9

X=9

3)34+(x-23)=69

34+x-23=69

11+x=69

X=69-11

X=58

4)(156x)-61=72

156x=72+61

156x=133

X= 133/156 дробью

Пошаговое объяснение:

Answer 3

It looks like you've provided a set of equations with variables. You probably want to solve for the values of the variables in each equation. Let's solve them one by one:

1. $77 - (45 + x) = 13$: First, simplify the equation inside the parentheses: $77 - 45 - x = 13$ $32 - x = 13$ Now, isolate $x$ by subtracting 32 from both sides: $-x = -19$ Finally, multiply both sides by -1 to solve for $x$: $x = 19$

2. $(30 - x) + 21 = 42$: First, combine like terms on the left side: $51 - x = 42$ Now, isolate $x$ by subtracting 51 from both sides: $-x = -9$ Multiply both sides by -1 to solve for $x$: $x = 9$

3. $34 + (x - 23) = 69$: First, simplify the equation inside the parentheses: $34 + x - 23 = 69$ $x + 11 = 69$ Now, isolate $x$ by subtracting 11 from both sides: $x = 58$

4. $156x - 61 = 72$: Add 61 to both sides to isolate the term with $x$: $156x = 133$ Now, divide both sides by 156 to solve for $x$: $x = \frac{133}{156}$

5. $324 - (x + 52) = 223$: First, simplify the equation inside the parentheses: $324 - x - 52 = 223$ $272 - x = 223$ Now, isolate $x$ by subtracting 272 from both sides: $-x = -49$ Multiply both sides by -1 to solve for $x$: $x = 49$

These are the solutions for the variables in each equation.