Question

Б)6 5/6 +2 3/8в)4 5/14+(5 1/12-3 4/21)​

Answer 1

б) 6 5/6 + 2 3/8 = 6 20/24 + 2 9/24 = 8 29/24 = 9 целых 5/24

в) 4 5/14 + (5 1/12 - 3 4/21) = 6 целых 1/4

1) 5 1/12 - 3 4/21 = 5 7/84 - 3 16/84 = 4 91/84 - 3 16/84 = 1 75/84 = 1 25/28

2) 4 5/14 + 1 25/28 = 4 10/28 + 1 25/28 = 5 35/28 = 5 5/4 = 6 1/4

Answer 2

Пошаговое объяснение:

как то так...........

Answer 3

Let's solve these arithmetic expressions step by step:

а) $6 \frac{5}{6} + 2 \frac{3}{8}$

First, let's convert the mixed numbers to improper fractions: $6 \frac{5}{6} = \frac{6 \cdot 6 + 5}{6} = \frac{41}{6}$ $2 \frac{3}{8} = \frac{2 \cdot 8 + 3}{8} = \frac{19}{8}$

Now, add the two fractions: $\frac{41}{6} + \frac{19}{8}$

To add fractions with different denominators, we need a common denominator. In this case, the least common multiple (LCM) of 6 and 8 is 24. Let's rewrite the fractions with a common denominator of 24:

$\frac{41}{6} \cdot \frac{4}{4} = \frac{164}{24}$ $\frac{19}{8} \cdot \frac{3}{3} = \frac{57}{24}$

Now we can add the fractions: $\frac{164}{24} + \frac{57}{24} = \frac{221}{24}$

Now, let's convert the improper fraction back to a mixed number: $\frac{221}{24} = 9 \frac{13}{24}$

So, $6 \frac{5}{6} + 2 \frac{3}{8} = 9 \frac{13}{24}$.

b) $4 \frac{5}{14} + \left(5 \frac{1}{12} - 3 \frac{4}{21}\right)$

First, let's convert the mixed numbers to improper fractions: $4 \frac{5}{14} = \frac{4 \cdot 14 + 5}{14} = \frac{61}{14}$ $5 \frac{1}{12} = \frac{5 \cdot 12 + 1}{12} = \frac{61}{12}$ $3 \frac{4}{21} = \frac{3 \cdot 21 + 4}{21} = \frac{67}{21}$

Now let's deal with the inner expression first: $5 \frac{1}{12} - 3 \frac{4}{21}$ $\frac{61}{12} - \frac{67}{21}$

To subtract fractions with different denominators, again, we need a common denominator. The LCM of 12 and 21 is 84. Let's rewrite the fractions with a common denominator of 84:

$\frac{61}{12} \cdot \frac{7}{7} = \frac{427}{84}$ $\frac{67}{21} \cdot \frac{4}{4} = \frac{268}{84}$

Now we can subtract the fractions: $\frac{427}{84} - \frac{268}{84} = \frac{159}{84}$