Question

(x-1)(x+2)>(x-2)(x+3)​

Answer 1

Ответ:

Равно (6)=(7)8)))))))))))))))))))))))))))

Answer 2

To solve the inequality $(x-1)(x+2) > (x-2)(x+3)$, you can start by expanding both sides of the inequality:

$(x-1)(x+2) > (x-2)(x+3)$

Expanding the left side:

$x^2 + 2x - x - 2 > (x-2)(x+3)$

Simplifying the left side:

$x^2 + x - 2 > (x-2)(x+3)$

Now, expand the right side:

$x^2 + x - 2 > x^2 + 3x - 2x - 6$

Simplifying the right side:

$x^2 + x - 2 > x^2 + x - 6$

Now, subtract $x^2 + x$ from both sides of the inequality to simplify it further:

$-2 > -6$

This is a true statement because -2 is indeed less than -6. Therefore, the solution to the inequality $(x-1)(x+2) > (x-2)(x+3)$ is:

$x$ can be any real number because the inequality is always true.