Question

1) 2x2 - 7x + 6 = 0;3) 5x2 - 12x + 4 = 0;​

Answer 1

Я так понимаю, это дискриминант.

1) 2x²-7x+6 = 0

a=2, b=-7, c=6

D = b²-4ac = (-7²)-4*2*6 = 49-48 = 1 > 0, 2 корня.

$x = \frac{-b+-\sqrt{D} }{2a}$

$x_1 = \frac{7+1}{4} = 2$

$x_2 = \frac{7-1}{4} = 1,5$

Ответ: 1,5;2.

2) 5x²-12x+4 = 0

a=5, b=-12, c=4

D = 144-4*5*4 = 144-80 = √64 = 8 > 0, 2 корня.

$x_1 = \frac{12+8}{10} = 2$

$x_2 = \frac{12-8}{10} = 0,4$

Ответ: 0,4;2.

Answer 2

Ответ:

1.х=2

3.х=2

Пошаговое объяснение:

ето уравнение

Answer 3

To solve the quadratic equations you provided, we can use the quadratic formula, which is given by:

x = (-b ± √(b² - 4ac)) / (2a)

Let's solve each equation separately:

1. 2x² - 7x + 6 = 0

Comparing this equation with the standard form (ax² + bx + c = 0), we have: a = 2, b = -7, c = 6

Substituting these values into the quadratic formula, we get:

x = (-(-7) ± √((-7)² - 4 * 2 * 6)) / (2 * 2) x = (7 ± √(49 - 48)) / 4 x = (7 ± √1) / 4

x = (7 + 1) / 4 or x = (7 - 1) / 4 x = 8 / 4 or x = 6 / 4 x = 2 or x = 3/2

Therefore, the solutions for the equation 2x² - 7x + 6 = 0 are x = 2 and x = 3/2.

3. 5x² - 12x + 4 = 0

Comparing this equation with the standard form, we have: a = 5, b = -12, c = 4

Using the quadratic formula:

x = (-(-12) ± √((-12)² - 4 * 5 * 4)) / (2 * 5) x = (12 ± √(144 - 80)) / 10 x = (12 ± √64) / 10 x = (12 ± 8) / 10

x = (12 + 8) / 10 or x = (12 - 8) / 10 x = 20 / 10 or x = 4 / 10 x = 2 or x = 2/5

Therefore, the solutions for the equation 5x² - 12x + 4 = 0 are x = 2 and x = 2/5.