
(7- 2/3)÷(1 3/4-1/6)×(1 1/5+2 2/3 +1/6)=


Ответы на вопрос

Ответ:
Вот. Всё на фотографии
Пошаговое объяснение:
Я в математике ас.
Если будут вопросы подпишись я буду помогать




To solve this expression step by step, follow the order of operations (PEMDAS/BODMAS: Parentheses/Brackets, Exponents/Orders, Multiplication and Division [from left to right], Addition and Subtraction [from left to right]).
Step 1: Evaluate the expressions within the parentheses/brackets first.
- 7 - 2/3 = 21/3 - 2/3 = 19/3
- 1 3/4 - 1/6 = 7/4 - 1/6 = 42/24 - 4/24 = 38/24 = 19/12
- 1 1/5 + 2 2/3 + 1/6 = (5/5 + 1/5) + (15/5 + 2/3) + (1/6) = 6/5 + 47/15 + 1/6
Now, let's find a common denominator for these fractions:
Step 2: Find a common denominator.
The common denominator for 5, 15, and 6 is 30.
- 6/5 (multiply numerator and denominator by 6 to get a common denominator of 30): 36/30
- 47/15 (multiply numerator and denominator by 2 to get a common denominator of 30): 94/30
- 1/6 (multiply numerator and denominator by 5 to get a common denominator of 30): 5/30
Now, we have:
6/5 + 47/15 + 1/6 = 36/30 + 94/30 + 5/30
Step 3: Add the fractions:
(36/30 + 94/30 + 5/30) = (36 + 94 + 5) / 30 = 135/30
Step 4: Simplify the fraction:
135/30 can be simplified by dividing both the numerator and denominator by their greatest common divisor, which is 15:
(135 ÷ 15) / (30 ÷ 15) = 9/2
Now that we have simplified the expressions within the parentheses and brackets, we can proceed with the multiplication and division outside the parentheses and brackets.
Step 5: Perform the multiplication and division:
(19/3) ÷ (19/12) × (9/2)
Now, invert and multiply:
(19/3) × (12/19) × (9/2)
Step 6: Multiply the fractions:
(19 * 12 * 9) / (3 * 19 * 2)
Step 7: Simplify the fraction:
(2052) / (114)
Step 8: If possible, simplify further by finding the greatest common divisor of the numerator and denominator, but in this case, there is no common divisor other than 1.
So, the final result is:
2052 / 114 = 17
The expression (7 - 2/3) ÷ (1 3/4 - 1/6) × (1 1/5 + 2 2/3 + 1/6) equals 17.


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