Question

(7-2/3):(1 3/4-1/6)*(1 1/5+2 2/3+1/6​

Answer 1

Ответ:(7-2/3):(1 3/4-1/6)*(1 1/5+2 2/3+1/6)

1)7-2/3=6 3/3-2/3=6 1/3

2)1 3/4-1/6=1 9/12-2/12=1 7/12

3)1 1/5+2 2/3=1 3/15+2 10/15=3 13/15

4)3 13/15+1/6=3 26/30+5/30=3 31/30=4 1/30

5)6 1/3:1 7/12=19/3:19/12=19/3*12/19=1/1*4/1=1*4=4

6)4*4 1/30=4*121/30=484/30=16 4/30=16 2/15

Ответ:17 2/17

Пошаговое объяснение:Ответ Может быть 16 2/15 но это не точно но я советую это: 16 2/15

Answer 2

To solve this expression, you should follow the order of operations (PEMDAS/BODMAS), which stands for Parentheses/Brackets, Exponents/Orders (i.e., powers and square roots, etc.), Multiplication and Division (left-to-right), and Addition and Subtraction (left-to-right).

First, let's simplify each part of the expression step by step:

1. Simplify the fractions:

   • $7 - \frac{2}{3} = \frac{21}{3} - \frac{2}{3} = \frac{19}{3}$

   • $1 \frac{3}{4} = \frac{4}{4} + \frac{3}{4} = \frac{7}{4}$

   • $1 \frac{1}{5} = \frac{5}{5} + \frac{1}{5} = \frac{6}{5}$

   • $2 \frac{2}{3} = \frac{6}{3} + \frac{2}{3} = \frac{8}{3}$

   • $\frac{1}{6} = \frac{1}{6}$

2. Next, perform the operations inside the parentheses:

   $\frac{19}{3} : \left( \frac{7}{4} - \frac{1}{6} \right) \left( \frac{6}{5} + \frac{8}{3} + \frac{1}{6} \right)$

3. Now, work on the innermost operations:

   • $\frac{7}{4} - \frac{1}{6} = \frac{42}{24} - \frac{4}{24} = \frac{38}{24} = \frac{19}{12}$

   • $\frac{6}{5} + \frac{8}{3} + \frac{1}{6} = \frac{36}{30} + \frac{80}{30} + \frac{5}{30} = \frac{121}{30}$

4. Substitute these results back into the main expression:

   $\frac{19}{3} : \left( \frac{19}{12} \right) \left( \frac{121}{30} \right)$

5. Now, multiply and divide:

   $\frac{19}{3} \cdot \frac{12}{19} \cdot \frac{30}{121}$

6. Simplify:

   $\frac{1}{3} \cdot \frac{4}{1} \cdot \frac{5}{11}$

7. Multiply the fractions:

   $\frac{1 \cdot 4 \cdot 5}{3 \cdot 1 \cdot 11} = \frac{20}{33}$

So, the final result is $\frac{20}{33}$