Question

-(2,1a-1,3y)+(2,5y-0,8)-(-12a+2,8y)=

Answer 1

Ответ:

-(2,1a-1,3y)+(2,5y-0,8)-(-12a+2,8y)= -2,1a+1,3y+2,5y-0,8+12a-2,8y=9,9a+y-0,8

Пошаговое объяснение:

Answer 2

Let's simplify the given expression step by step:

-(2,1a - 1,3y) + (2,5y - 0,8) - (-12a + 2,8y)

First, distribute the negative sign inside the first set of parentheses:

-2,1a + 1,3y + (2,5y - 0,8) - (-12a + 2,8y)

Now, remove the parentheses:

-2,1a + 1,3y + 2,5y - 0,8 + 12a - 2,8y

Next, group like terms (terms with 'a' and terms with 'y'):

(-2,1a + 12a) + (1,3y + 2,5y - 2,8y) - 0,8

Now, perform the additions/subtractions:

(12a - 2,1a) + (1,3y + 2,5y - 2,8y) - 0,8

10,9a + 0,0y - 0,8

Finally, since 0 times any number is still 0, we can simplify further:

10,9a - 0,8

So, the simplified expression is:

10,9a - 0,8