Question

(3x - 1) (2х+3)=3(2x-1)​

Answer 1

ответ:

пошаговое объяснение:

Answer 2

Ответ:

(3x - 1) (2х+3) =3(2x-1)​

В левой стороне: умножаем скобки друг на друга каждое число

$6x^{2} +9x-2x-3=3(2x-1)$

В правой стороне: умножаем 3 на каждое число внутри скобки

$6x^{2} +9x-2x-3=6x-3$

$6x^{2} +7x-3=6x-3\\6x^{2} +x=0\\x(6x+1)=0\\x_{1} =0\\6x+1=0\\6x=-1\\x_{2} =-\frac{1}{6}$

Ответ: $x_{1} =0, x_{2} =-\frac{1}{6}$

Answer 3

To solve the equation (3x - 1)(2x + 3) = 3(2x - 1), you can follow these steps:

1. Expand both sides of the equation by applying the distributive property (FOIL):

   (3x - 1)(2x + 3) = 3(2x - 1)

   6x^2 + 9x - 2x - 3 = 6x - 3

2. Simplify the equation by combining like terms:

   6x^2 + 7x - 3 = 6x - 3

3. Now, subtract 6x from both sides of the equation to get all the x terms on one side:

   6x^2 + 7x - 6x - 3 = -3

4. Simplify further:

   6x^2 + x - 3 = -3

5. Subtract -3 from both sides to isolate the quadratic expression:

   6x^2 + x = 0

6. Factor out x from the left side:

   x(6x + 1) = 0

Now, you have a factored equation. To find the solutions for x, set each factor equal to zero:

1. x = 0
2. 6x + 1 = 0

For the second equation (6x + 1 = 0), subtract 1 from both sides:

6x = -1

Finally, divide by 6 to solve for x:

x = -1/6

So, the solutions to the equation (3x - 1)(2x + 3) = 3(2x - 1) are x = 0 and x = -1/6.