Question

(a+b) ×c=ac+bc a=0,2b-0,3c=-0,5​

Answer 1

Ответ:

0,05

Пошаговое объяснение:

0,2*(-0,5)+(-0,3)*(-0,5)=-0,1+0,15=0,05

Answer 2

To solve the given equations, let's substitute the value of 'a' in the second equation into the first equation:

(a + b) × c = ac + bc (0 + b) × c = 0c + bc b × c = bc

Now, let's solve the second equation to find the values of 'b' and 'c':

2b - 0.3c = -0.5

Let's rearrange this equation to isolate 'b':

2b = 0.3c - 0.5 b = (0.3c - 0.5) / 2

Substitute this value of 'b' into the first equation:

(0.3c - 0.5) / 2 × c = ((0 × c) + (0.3c - 0.5) / 2 × c) (0.3c - 0.5) / 2 × c = (0.3c² - 0.5c) / 2

Since we know that b × c = bc, we can equate the two expressions:

(0.3c - 0.5) / 2 × c = (0.3c² - 0.5c) / 2

Now, let's simplify the equation:

0.3c² - 0.5c = 0.3c² - 0.5c

The equation simplifies to 0 = 0. This means that the equation is an identity and is true for any value of 'c'.

Therefore, there are infinitely many solutions to the given system of equations.