Question

1) х²+9ху+14у²=02) 3х²-8ху+5у²=0​

Answer 1

Ответ:

Вот Ответ,это должно бытьправельным

Answer 2

These are two quadratic equations in variables x and y. Let's analyze each equation separately:

1. x² + 9xy + 14y² = 0

2. 3x² - 8xy + 5y² = 0

To find solutions to these equations, we can use the quadratic formula. The quadratic formula states that for an equation in the form of ax² + bx + c = 0, the solutions for x can be found using:

x = (-b ± √(b² - 4ac)) / (2a)

Let's apply this formula to each of your equations:

1. For x² + 9xy + 14y² = 0:

a = 1, b = 9y, and c = 14y²

Using the quadratic formula:

x = (-9y ± √((9y)² - 4(1)(14y²))) / (2(1))

x = (-9y ± √(81y² - 56y²)) / 2

x = (-9y ± √(25y²)) / 2

x = (-9y ± 5y) / 2

So, the solutions for x are:

x₁ = (-9y + 5y) / 2 = -2y/2 = -y

x₂ = (-9y - 5y) / 2 = -14y/2 = -7y

Therefore, the solutions for the first equation are x = -y and x = -7y.

2. For 3x² - 8xy + 5y² = 0:

a = 3, b = -8y, and c = 5y²

Using the quadratic formula:

x = (8y ± √((-8y)² - 4(3)(5y²))) / (2(3))

x = (8y ± √(64y² - 60y²)) / 6

x = (8y ± √(4y²)) / 6

x = (8y ± 2y) / 6

x₁ = (8y + 2y) / 6 = 10y/6 = 5y/3

x₂ = (8y - 2y) / 6 = 6y/6 = y

So, the solutions for the second equation are x = 5y/3 and x = y.

These are the solutions for the given quadratic equations in terms of x and y.