Question

7x-4(3x-2)<-8 ...........................

Answer 1

Решение и ответ:

$\displaystyle 7x-4(3x-2)$

$\displaystyle 7x-12x+8$

$\displaystyle -5x$

$\displaystyle -5x$

$>-16\div(-5)$

$\displaystyle \boxed{x>3.2}$

либо

$\displaystyle \boxed{x\in\left({3.2;+\infty}\right)}$

Answer 2

To solve the inequality 7x - 4(3x - 2) < -8, follow these steps:

1. Distribute the -4 to both terms inside the parentheses: 7x - 12x + 8 < -8

2. Combine like terms on the left side of the inequality: (7x - 12x) + 8 < -8 -5x + 8 < -8

3. Now, you want to isolate x on the left side. To do that, subtract 8 from both sides of the inequality: -5x + 8 - 8 < -8 - 8 -5x < -16

4. Finally, divide both sides by -5 to solve for x. Remember that when you divide by a negative number, the inequality sign flips: (-5x)/(-5) > (-16)/(-5) x > 16/5

So, the solution to the inequality is: x > 16/5