Question

A)[4x/3- 8] = 0b)[5х/2+ 15 ]= 0​

Answer 1

Ответ:

Первое х= 6

Второе х= -6

Пошаговое объяснение:

Answer 2

It seems like you have two equations that you want to solve for 'x'. Let's solve them one by one.

A) (4x/3 - 8) = 0

To solve this equation, we want to isolate 'x' on one side of the equation:

1. Add 8 to both sides:

   (4x/3 - 8) + 8 = 0 + 8

   4x/3 = 8

2. Multiply both sides by 3 to get rid of the fraction:

   (4x/3) * 3 = 8 * 3

   4x = 24

3. Finally, divide both sides by 4 to solve for 'x':

   (4x)/4 = 24/4

   x = 6

So, the solution for A) is x = 6.

B) (5x/2 + 15) = 0

To solve this equation, we want to isolate 'x' on one side of the equation:

1. Subtract 15 from both sides:

   (5x/2 + 15) - 15 = 0 - 15

   5x/2 = -15

2. Multiply both sides by 2 to get rid of the fraction:

   (5x/2) * 2 = -15 * 2

   5x = -30

3. Finally, divide both sides by 5 to solve for 'x':

   (5x)/5 = -30/5

   x = -6

So, the solution for B) is x = -6.

Therefore, the solutions for the two equations are:

A) x = 6 B) x = -6