Question

9x^2-4=0; 4x^2-25=0:

Answer 1

..............................

Answer 2

To solve these quadratic equations, you can use the quadratic formula:

For the first equation, 9x^2 - 4 = 0: a = 9 b = 0 c = -4

The quadratic formula is:

x = (-b ± √(b² - 4ac)) / (2a)

Plugging in the values:

x = (0 ± √(0² - 4 * 9 * (-4))) / (2 * 9)

x = (± √(0 + 144)) / 18

x = (± √144) / 18

x = (± 12) / 18

Now, simplify the fractions:

x = (± 2/3)

So, for the first equation, you have two solutions:

x = 2/3 and x = -2/3

Now, let's solve the second equation, 4x^2 - 25 = 0: a = 4 b = 0 c = -25

Using the quadratic formula again:

x = (-b ± √(b² - 4ac)) / (2a)

x = (0 ± √(0² - 4 * 4 * (-25))) / (2 * 4)

x = (± √(0 + 400)) / 8

x = (± √400) / 8

x = (± 20) / 8

Now, simplify the fractions:

x = (± 5/2)

So, for the second equation, you have two solutions:

x = 5/2 and x = -5/2