Question

7у-4(3у+5)-13(х-6)=14(2х+1)​

Answer 1

Ответ:

42х-66-13х+78=28х+14

29х+12=28х+14

Х=2

Answer 2

To solve the equation 7у - 4(3у + 5) - 13(х - 6) = 14(2х + 1), you'll want to follow these steps:

1. Distribute the constants on both sides of the equation:

   7у - 12у - 20 - 13х + 78 = 28х + 14

2. Combine like terms on both sides of the equation:

   (7у - 12у) + (-13х) + (-20 + 78) = 28х + 14

3. Simplify the equation further:

   -5у - 13х + 58 = 28х + 14

4. Move all the terms with x to one side of the equation and the constants to the other side:

   -5у - 13х - 28х = 14 - 58

5. Combine like terms:

   -5у - 41х = -44

6. Now, you can solve for y by isolating it on one side of the equation. Start by adding 41x to both sides:

   -5у = 41x - 44

7. Finally, divide both sides by -5 to solve for y:

   y = (41x - 44) / -5

So, the solution for the equation is:

y = (41x - 44) / -5