Question

5) 4x + 2 > 3x + 1;6) 6 x + 1 < 2x + 9.​

Answer 1

Ответ:

решение на фотографии

Answer 2

To solve these inequalities, you can follow similar steps as you would when solving equations. The main difference is that when you multiply or divide by a negative number, you need to reverse the inequality sign.

Let's solve each inequality:

5. $4x + 2 > 3x + 1$

First, subtract $3x$ from both sides of the inequality:

$4x - 3x + 2 > 1$

Now, simplify:

$x + 2 > 1$

Next, subtract 2 from both sides:

$x > 1 - 2$

$x > -1$

So, the solution to this inequality is $x > -1$.

6. $6x + 1 < 2x + 9$

First, subtract $2x$ from both sides of the inequality:

$6x - 2x + 1 < 9$

Now, simplify:

$4x + 1 < 9$

Next, subtract 1 from both sides:

$4x < 9 - 1$

$4x < 8$

Now, divide both sides by 4. Since we are dividing by a positive number (4), the inequality sign remains the same:

$x < 8 / 4$

$x < 2$

So, the solution to this inequality is $x < 2$.

Therefore, the solutions to the given inequalities are:

5. $x > -1$

6. $x < 2$