Question

3(×-1)<×-3 5(×+3)>2×+3

Answer 1

Ответ:

Пошаговое объяснение:

3(x-1)<x-3

3x-3<x-3

2x<0; x<0

x∈(-∞; 0)

5(x+3)>2x+3

5x+15>2x+3

3x>-12

x>-12/3; x>-4

x∈(-4; +∞)

Answer 2

To solve the inequalities:

1. 3(x - 1) < x - 3
2. 5(x + 3) > 2x + 3

Let's solve each one separately:

1. 3(x - 1) < x - 3:

First, distribute the 3 on the left side:

3x - 3 < x - 3

Now, move x to the left side by subtracting x from both sides:

3x - x - 3 < -3

2x - 3 < -3

Next, add 3 to both sides to isolate 2x:

2x - 3 + 3 < -3 + 3

2x < 0

Now, divide by 2:

2x/2 < 0/2

x < 0

So, the solution to the first inequality is:

x < 0

2. 5(x + 3) > 2x + 3:

First, distribute the 5 on the left side:

5x + 15 > 2x + 3

Now, move 2x to the left side by subtracting 2x from both sides:

5x - 2x + 15 > 3

3x + 15 > 3

Next, subtract 15 from both sides to isolate 3x:

3x + 15 - 15 > 3 - 15

3x > -12

Now, divide by 3:

3x/3 > -12/3

x > -4

So, the solution to the second inequality is:

x > -4

To summarize:

1. For the first inequality, x < 0.
2. For the second inequality, x > -4.