Question

№ 2. 1). 1 - 7/38= 2). 1 - 19/42 = 3). 5 - 1ц. 16/32 = 4). 5 - 19/20 =​

Answer 1

Ответ:

1)

$1 - \frac{7}{38} = \frac{38}{38} - \frac{7}{38} = \frac{31}{38}$

2)

$1 - \frac{19}{42} = \frac{42}{42} - \frac{19}{42} = \frac{23}{42}$

3)

$5 - 1\frac{16}{32} = 4\frac{32}{32} - 1\frac{16}{32} = 3\frac{16}{32} = 3\frac{1}{2}$

4)

$5 - \frac{19}{20} = 4\frac{20}{20} - \frac{19}{20} = 4\frac{1}{20}$

Пошаговое объяснение:

Думаю, что всё понятно.

Answer 2

Ответ: 1). 1 - 7/38= (38-7)/38 = 31/38

2). 1 - 19/42 = (42-19)/42 = 23/42

3). 5 - 1ц. 16/32 = 5- 48/32 = 7/2

4). 5 - 19/20 =​ (100-19)/20= 81/20= 4ц. 1/20

Пошаговое объяснение:

Answer 3

Let's calculate each of these expressions:

1. $1 - \frac{7}{38}$ To subtract fractions, you need a common denominator. The common denominator for 1 and 38 is 38. So, you can rewrite 1 as $\frac{38}{38}$ and then subtract:

$\frac{38}{38} - \frac{7}{38} = \frac{38 - 7}{38} = \frac{31}{38}$

2. $1 - \frac{19}{42}$ Again, you need a common denominator, which in this case is 42:

$\frac{42}{42} - \frac{19}{42} = \frac{42 - 19}{42} = \frac{23}{42}$

3. $5 - \frac{16}{32}$ In this case, both 5 and 16/32 have a common denominator of 32:

$5 - \frac{16}{32} = \frac{160}{32} - \frac{16}{32} = \frac{160 - 16}{32} = \frac{144}{32}$

To simplify this fraction, you can find the greatest common divisor (GCD) of 144 and 32, which is 32:

$\frac{144}{32} = \frac{144 \div 32}{32 \div 32} = \frac{4}{1} = 4$

So, $5 - \frac{16/32}{32} = 4$

4. $5 - \frac{19}{20}$ To subtract these fractions, you need a common denominator, which is 20:

$5 - \frac{19}{20} = \frac{100}{20} - \frac{19}{20} = \frac{100 - 19}{20} = \frac{81}{20}$

These are the results of the calculations for each expression:

1. $1 - \frac{7}{38} = \frac{31}{38}$

2. $1 - \frac{19}{42} = \frac{23}{42}$

3. $5 - \frac{16}{32} = 4$

4. $5 - \frac{19}{20} = \frac{81}{20}$