Question

((2-4)+(6-8)+(10-12)+...+(98-100)÷(-10)

Answer 1

Ответ:-2+-2+-2=-6

-2÷-10=-бесконечность

Пошаговое объяснение:

Answer 2

To calculate the expression:

(2 - 4) + (6 - 8) + (10 - 12) + ... + (98 - 100) ÷ (-10)

We need to perform each subtraction and then divide the final result by -10. Let's break it down step by step:

1. Calculate each pair of numbers inside the parentheses: (2 - 4) = -2 (6 - 8) = -2 (10 - 12) = -2 ... (98 - 100) = -2

2. Add up all these results: -2 + (-2) + (-2) + ... + (-2) = -2n, where n is the number of pairs.

3. Now, let's find the value of n, the number of pairs: We start with 2 and end with 100, incrementing by 4 each time. So, 2 + 4 + 4 + ... + 4 (n times) = 100 2 + 4n = 100 4n = 100 - 2 4n = 98 n = 98 / 4 n = 24.5

Since n is not a whole number (it's 24.5), we have an uneven number of pairs, which means we'll have 24 pairs of (-2) and one additional (-2) remaining.

4. Now, add up all the pairs and the remaining (-2): -2n = -2 * 24.5 = -49

5. Finally, divide the result by -10: -49 / -10 = 4.9

So, the value of the expression is 4.9.