Question

2) 3x + 2 - x= 6;3) 3(x - 1) - x = 0;4) 7 – 3y + 4y – 4=-1.​

Answer 1

2) 3x + 2 – x = 6

3x – x = 6 – 2

2x = 4

x = 4 / 2 = 2

3) 3(x – 1) – x = 0

3x – 3 – x = 0

3x – x = 3

2x = 3

x = 3/2

4) 7 – 3y + 4y – 4 = –1

4y – 3y = 4 – 7 – 1

y = –4

Answer 2

Let's solve each of these equations step by step:

2. 3x + 2 - x = 6 Combine like terms: 2x + 2 = 6

Subtract 2 from both sides to isolate 2x: 2x = 6 - 2 2x = 4

Now, divide by 2 to find the value of x: x = 4 / 2 x = 2

So, the solution to the equation is x = 2.

3. 3(x - 1) - x = 0 Distribute the 3 on the left side of the equation: 3x - 3 - x = 0

Combine like terms: 2x - 3 = 0

Add 3 to both sides to isolate 2x: 2x = 3

Now, divide by 2 to find the value of x: x = 3 / 2 x = 1.5

So, the solution to the equation is x = 1.5.

4. 7 - 3y + 4y - 4 = -1 Combine like terms on the left side of the equation: (7 - 4) + (4y - 3y) = -1 3 + y = -1

Subtract 3 from both sides to isolate y: y = -1 - 3 y = -4

So, the solution to the equation is y = -4.