Question

(4x+16)×(2,4+0,3x)=0

Answer 1

$(4x+16)*(2,4+0,3x)=0\\9,6x+1,2x^2+38,4+4,8x=0\\1,2x^2+14,4x+38,4=0\\D=14,4^{2} -4*1,2*38,4=207,36-184,32=23,04\\\\x1=\frac{-14,4-\sqrt{23,04} }{2*1,2} =\frac{-14,4-4,8 }{2,4}=\frac{-19,2}{2,4} =-8\\\\x1=\frac{-14,4+\sqrt{23,04} }{2*1,2} =\frac{-14,4+4,8 }{2,4}=\frac{-9,6}{2,4} =-4$

Ответ: x₁=-8; x₂=-4

Answer 2

Ответ:

х первый = -8

х второй = -4

Решение на фото.

Answer 3

To solve the equation (4x+16)×(2.4+0.3x) = 0, you can use the zero-product property, which states that if the product of two factors equals zero, then at least one of the factors must be equal to zero. So, you'll set each factor equal to zero and solve for x:

1. Set 4x + 16 = 0: 4x + 16 = 0 4x = -16 x = -16/4 x = -4

2. Set 2.4 + 0.3x = 0: 2.4 + 0.3x = 0 0.3x = -2.4 x = -2.4 / 0.3 x = -8

So, there are two solutions for x: x = -4 and x = -8. These are the values of x that make the equation (4x+16)×(2.4+0.3x) = 0 true.