Question

3)|4,2x-1|=0. 2)2|x|+7=0;

Answer 1

Ответ:

3)х=1/4.2 2) х=корней нет

Пошаговое объяснение:

Answer 2

Let's solve the equations step by step.

1. $3|4-2x|=1$:

First, we can split this into two cases:

Case 1: $4-2x$ is non-negative, giving us:

$3(4-2x)=1$
$12-6x=1$
$6x=11$
$x=\frac{11}{6}$

Case 2: $4-2x$ is negative, giving us:

$3(2x-4)=1$
$6x-12=1$
$6x=13$
$x=\frac{13}{6}$

So, the solutions for $2x-1$ are $\frac{11}{6}$ and $\frac{13}{6}$.

2. $2|x|+7=0$:

We isolate the absolute value term:

$2|x|=-7$

This equation doesn't have a real solution since an absolute value cannot be negative. So, there are no real solutions for this equation.