Question

(5х+30)•4/9=0 (3х-4)•5=0

Answer 1

Ответ:

1) х= 1/4

1) х=1

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Answer 2

To solve the equations $(5x+30)\cdot\frac{4}{9} = 0$ and $(3x-4)\cdot5 = 0$, you need to find the values of $x$ that satisfy each equation.

For the first equation: $(5x+30)\cdot\frac{4}{9} = 0$ Multiply both sides by $\frac{9}{4}$ to get rid of the fraction: $5x + 30 = 0$ Now, subtract 30 from both sides: $5x = -30$ Divide by 5: $x = -6$

For the second equation: $(3x-4)\cdot5 = 0$ Divide both sides by 5: $3x - 4 = 0$ Add 4 to both sides: $3x = 4$ Divide by 3: $x = \frac{4}{3}$

So, the solutions to the given equations are $x = -6$ and $x = \frac{4}{3}$.