Question

1426. 1) [4x + 3y - 5 = 0,Ix-y-3= 0;​

Answer 1

Ответ:

решение смотри на фотографии

Answer 2

It seems like you've provided two linear equations:

1. 4x + 3y - 5 = 0
2. x - y - 3 = 0

These equations can be solved simultaneously to find the values of x and y that satisfy both equations. There are several methods to solve such a system of equations, but I'll use the substitution method:

First, let's solve the second equation (2) for x: x = y + 3

Now, we can substitute this expression for x into the first equation (1):

4(y + 3) + 3y - 5 = 0

Now, simplify and solve for y:

4y + 12 + 3y - 5 = 0 7y + 7 = 0

Subtract 7 from both sides:

7y = -7

Now, divide by 7 to isolate y:

y = -1

Now that you have the value of y, you can substitute it back into one of the original equations to find the value of x. Let's use equation (2):

x = y + 3 x = (-1) + 3 x = 2

So, the solution to the system of equations is:

x = 2 y = -1