Question

2х-2у=4 3х-2у=-1.............................

Answer 1

Ответ:

(-5 ; -7).

Пошаговое объяснение:

{2х-2у=4 |*(-1)

{3х-2у=-1

{-2х+2у=-4

{3х-2у=-1

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х = -5

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3(-5)-2у=-1

-15-2у=-1

-2у=14

у=-7

Answer 2

To solve this system of equations:

1. 2x - 2y = 4
2. 3x - 2y = -1

You can use the method of substitution or elimination. Let's use the elimination method to eliminate the variable y. We can do this by multiplying one of the equations by a suitable factor that makes the coefficients of y in both equations cancel each other when added.

First, let's multiply the first equation (1) by 3 and the second equation (2) by 2 so that the coefficients of y in both equations will cancel out when added:

1. (3 * (2x - 2y)) = 3 * 4
2. (2 * (3x - 2y)) = 2 * (-1)

This simplifies the equations to:

1. 6x - 6y = 12
2. 6x - 4y = -2

Now, you can subtract equation (2) from equation (1) to eliminate x:

(6x - 6y) - (6x - 4y) = 12 - (-2)

This simplifies to:

-2y = 14

Now, divide both sides by -2 to solve for y:

y = -7

Now that you've found the value of y, you can substitute it back into one of the original equations to solve for x. Let's use the first equation (1):

2x - 2(-7) = 4 2x + 14 = 4

Subtract 14 from both sides:

2x = 4 - 14 2x = -10

Now, divide both sides by 2 to solve for x:

x = -10 / 2 x = -5

So, the solution to the system of equations is:

x = -5 y = -7