Question

5x-2y=6,7x+2=6;x+3y=6,2x+y=7;​

Answer 1

Вот решение! Всегда пожалуйста ;)

Answer 2

It seems like you have two systems of linear equations, and you'd like to find the solutions for both. Let's solve each system separately.

System 1:

1. 5x - 2y = 6
2. 7x + 2 = 6

Let's start with the second equation:

From equation 2: 7x + 2 = 6 Subtract 2 from both sides: 7x = 4 Divide by 7: x = 4/7

Now, substitute this value into equation 1:

5(4/7) - 2y = 6 (20/7) - 2y = 6

Subtract (20/7) from both sides:

-2y = 6 - 20/7 -2y = (42/7) - (20/7) -2y = 22/7

Divide by -2:

y = (22/7) / -2 y = (22/7) * (-1/2) y = -11/7

So, for System 1, the solution is:

x = 4/7 y = -11/7

Now, let's move on to System 2:

System 2:

1. x + 3y = 6
2. 2x + y = 7

We can use the method of substitution to solve this system. Solve equation 1 for x:

x = 6 - 3y

Now, substitute this expression for x into equation 2:

2(6 - 3y) + y = 7

Distribute the 2:

12 - 6y + y = 7

Combine like terms:

12 - 5y = 7

Subtract 12 from both sides:

-5y = 7 - 12 -5y = -5

Now, divide by -5 to solve for y:

y = -5 / -5 y = 1

Now that we have the value of y, substitute it back into the expression for x:

x = 6 - 3(1) x = 6 - 3 x = 3

So, for System 2, the solution is:

x = 3 y = 1

You have the solutions for both systems:

System 1: x = 4/7 y = -11/7

System 2: x = 3 y = 1