Question

27+(х-41)=52 і 87-(у-25)=83​

Answer 1

Ответ:

1)27+(х-41)=52

х-41=52+27

х=79-41

х=52

Answer 2

To solve the system of equations:

1. $27 + (x - 41) = 52$
2. $87 - (y - 25) = 83$

Let's solve for $x$ and $y$ separately.

For the first equation:

$27 + (x - 41) = 52$

First, simplify the equation by removing the parentheses:

$27 + x - 41 = 52$

Now, combine like terms:

$x - 14 = 52$

Add 14 to both sides to isolate $x$:

$x = 52 + 14$

$x = 66$

Now, let's solve for $y$ in the second equation:

$87 - (y - 25) = 83$

First, simplify the equation by removing the parentheses:

$87 - y + 25 = 83$

Now, combine like terms:

$-y + 112 = 83$

Subtract 112 from both sides to isolate (y:

$-y = 83 - 112$

$-y = -29$

Multiply both sides by -1 to solve for (y:

$y = 29$

So, the solution to the system of equations is:

$x = 66$ and $y = 29$.