Question

15x +11y - 47 = 0,5x – y +17 = 0;​

Answer 1

{ 15x + 11y = 47 |

{ 5x - y = - 17 | *-3

15x + 11y = 47

+

-15x + 3y = 51

------------------------

14y = 98

y = 7

5x - 7 = - 17

5x = -17 + 7

5x = -10

x = -2

Ответ : (-2; 7)

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Answer 2

You have a system of two linear equations with two variables, x and y. You can solve this system of equations using the method of substitution or elimination. I'll show you how to solve it using the elimination method:

1. First, let's rewrite the two equations:

   Equation 1: 15x + 11y - 47 = 0 Equation 2: 5x - y + 17 = 0

2. We can multiply Equation 2 by 11 to make the coefficients of y in both equations cancel each other out. This is done to eliminate one of the variables (y):

   Multiply Equation 2 by 11: 11(5x - y + 17) = 11(0) 55x - 11y + 187 = 0

3. Now, we have the equations:

   Equation 1: 15x + 11y - 47 = 0 Equation 2: 55x - 11y + 187 = 0

4. Add the two equations together to eliminate y:

   (15x + 11y - 47) + (55x - 11y + 187) = 0

   15x + 55x - 47 + 187 = 0

5. Combine like terms:

   70x + 140 = 0

6. Subtract 140 from both sides of the equation:

   70x = -140

7. Divide by 70 to solve for x:

   x = -140 / 70 x = -2

8. Now that you have the value of x, you can substitute it into one of the original equations to solve for y. Let's use Equation 1:

   15x + 11y - 47 = 0 15(-2) + 11y - 47 = 0

   -30 + 11y - 47 = 0

9. Add 30 and 47 to both sides:

   11y = 30 + 47

10. Combine like terms:

11y = 77

11. Finally, divide by 11 to solve for y:

y = 77 / 11 y = 7

So, the solution to the system of equations is:

x = -2 y = 7