Question

(x – 8y - 17 = 0,3x + 4y – 23 = 0;​

Answer 1

Х-8у-17=0
3х+4у-23=0

Х-8у=17
3х+4у=23. *2

Х-8у=17
6х+8у=46

7х=63
Х-8у=17

Х=9
8у=9-17

Х=9
У=-1

Answer 2

To solve the system of linear equations:

1. $x - 8y - 17 = 0$
2. (3x + 4y - 23 = 0

You can use the method of either substitution or elimination. I'll use the elimination method in this case.

First, you want to eliminate one of the variables (either x or y) by adding or subtracting the equations. Let's eliminate y:

Multiply the first equation by 4 and the second equation by 8 so that when you add them together, the y terms cancel out:

1. $4(x - 8y - 17) = 4(0)$ (Multiplying the first equation by 4) $4x - 32y - 68 = 0$

2. $8(3x + 4y - 23) = 8(0)$ (Multiplying the second equation by 8) $24x + 32y - 184 = 0$

Now, add the two equations to eliminate the y terms:

$4x - 32y - 68 + 24x + 32y - 184 = 0$

Combine like terms:

$28x - 252 = 0$

Now, solve for x:

$28x = 252$

Divide both sides by 28:

$x = 252 / 28$ $x = 9$

Now that you have found the value of x, you can substitute it back into one of the original equations to solve for y. Let's use the first equation:

$x - 8y - 17 = 0$

$9 - 8y - 17 = 0$

Combine like terms:

$-8y - 8 = 0$

Now, isolate y by adding 8 to both sides:

$-8y = 8$

Divide both sides by -8:

$y = -1$

So, the solution to the system of equations is $x = 9$ and $y = -1$.