Question

|х+2|=3. |х-3|=0.............​

Answer 1

Ответ:

$-5; \quad 1;$

$3;$

Пошаговое объяснение:

$|x+2|=3;$

$x+2=-3 \quad \vee \quad x+2=3;$

$x=-3-2 \quad \vee \quad x=3-2;$

$x=-5 \quad \vee \quad x=1;$

_______________________

$|x-3|=0;$

$x-3=0;$

$x=3;$

Answer 2

Ответ:

1)|x+2|=3

x+2=3                 x+2=-3

x=3-2=1              x=-3-2=-5

2)|x-3|=0

x-3=0

x=3

Пошаговое объяснение:

Answer 3

To solve the equations |x + 2| = 3 and |x - 3| = 0, you can follow these steps:

1. Solve |x + 2| = 3: First, break it down into two cases: Case 1: x + 2 = 3 Case 2: x + 2 = -3

   Solve for x in each case: Case 1: x + 2 = 3 x = 3 - 2 x = 1

   Case 2: x + 2 = -3 x = -3 - 2 x = -5

2. Solve |x - 3| = 0: The absolute value of any real number is always non-negative, and it's only equal to zero when the number inside is zero. So, for this equation: x - 3 = 0 x = 3

So, the solutions to the two equations are:

1. For |x + 2| = 3: x = 1 x = -5

2. For |x - 3| = 0: x = 3