Question

(x+y= 6х/2-y/3=2x-y/4​

Answer 1

Ответ:

x=8

Пошаговое объяснение:

x/2- y/3=2x-y/4 | 12

6x-4y=6x-3y

6x-6x+3y-4y=0

y=0

x+0=8

x=8

Answer 2

It looks like you have a system of linear equations with two variables, x and y. You can solve this system of equations using either the substitution method or the elimination method. Let's use the elimination method.

The system of equations is:

1. x + y = 6
2. 6x/2 - y/3 = 2x - y/4

First, simplify equation 2:

1. 3x - y/3 = 2x - y/4 (multiply both sides by 3 to get rid of fractions)
2. 3(3x - y/3) = 3(2x - y/4)
3. 9x - y = 6x - y/4

Now, let's subtract equation 2 from equation 1 to eliminate the variable y: (x + y) - (9x - y) = 6 - (6x - y/4)

Simplify: x + y - 9x + y = 6 - 6x + y/4

Now, combine like terms: (1 - 9)x + (1 + 1/4)y = 6 - 6x

Simplify further: -8x + (5/4)y = 6 - 6x

Now, let's isolate y by moving the terms with y to one side of the equation: (5/4)y = 6 - 6x + 8x

Combine like terms on the right side: (5/4)y = 6 + 2x

Now, divide both sides by (5/4) to solve for y: y = (4/5)(6 + 2x)

y = (4/5)(6) + (4/5)(2x)

y = (24/5) + (8/5)x

Now, we have expressions for both x and y in terms of each other: x = 6 - y y = (24/5) + (8/5)x

You can use these equations to solve for the values of x and y. If you plug the expression for x into the equation for y, you can find the values of both variables.