Question

X2+6x−7=0 x_{1} = x_{2} =

Answer 1

Ответ:

Д=6^2-4*1*(-7)=36+28=64

x1=(-6-8)/2=-7

x2=(-6+8)/2=1

Пошаговое объяснение:

Answer 2

To find the solutions for the quadratic equation x^2 + 6x - 7 = 0, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 1, b = 6, and c = -7. Now, plug these values into the formula:

x = (-6 ± √(6² - 4(1)(-7))) / (2(1))

x = (-6 ± √(36 + 28)) / 2

x = (-6 ± √64) / 2

Now, calculate the two possible solutions:

1. x₁ = (-6 + √64) / 2 = (-6 + 8) / 2 = 2 / 2 = 1
2. x₂ = (-6 - √64) / 2 = (-6 - 8) / 2 = -14 / 2 = -7

So, the solutions to the equation x^2 + 6x - 7 = 0 are:

x₁ = 1 x₂ = -7