Question

2*(5-2х) = (3х-10)*(-3)= ? 3(х+4)=5(2+х)= ? (3х+1)*4= -5(х+6)= ? (2х+5)*(-6)=1-2х)*10= ? 3(6-х)=(х+1)*(-10)= ? 2*(3х+10)= -(2+х)-13= ?

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

2*(5-2х) = (3х-10)*(-3)

10 - 4x = -9x + 30

5x = 20

x = 4

3(х+4)=5(2+х)

3x + 12 = 10 +5x

-2x = -2

x = 1

(3х+1)*4= -5(х+6)

12x + 4 = -5x-30

17x = - 34

x = -2

(2х+5)*(-6)=1-2х)*10

-12x-30=10 -20x

8x=40

x=5

3(6-х)=(х+1)*(-10)

18 - 3x=-10x-10

7x= -28

x=-4

2*(3х+10)= -(2+х)-13

6x+20= - 15 +x

5x= -35

x= -7

Пошаговое объяснение:

9

Answer 3

Let's go through each equation one by one:

1. $2(5 - 2x) = (3x - 10)(-3)$:

   Distribute on both sides:

   $10 - 4x = -9x + 30$

   Add $4x$ to both sides:

   $10 = -5x + 30$

   Subtract $30$ from both sides:

   $-20 = -5x$

   Divide both sides by $-5$:

   $x = 4$

2. $3(x + 4) = 5(2 + x)$:

   Distribute on both sides:

   $3x + 12 = 10 + 5x$

   Subtract $3x$ from both sides:

   $12 = 7x + 10$

   Subtract $10$ from both sides:

   $2 = 7x$

   Divide both sides by $7$:

   $x = \frac{2}{7}$

3. $(3x + 1) \cdot 4 = -5(x + 6)$:

   Distribute on both sides:

   $12x + 4 = -5x - 30$

   Add $5x$ to both sides:

   $17x + 4 = -30$

   Subtract $4$ from both sides:

   $17x = -34$

   Divide both sides by $17$:

   $x = -2$

4. $(2x + 5)(-6) = (1 - 2x) \cdot 10$:

   Distribute on both sides:

   $-12x - 30 = 10 - 20x$

   Add $20x$ to both sides:

   $8x - 30 = 10$

   Add $30$ to both sides:

   $8x = 40$

   Divide both sides by $8$:

   $x = 5$

5. $3(6 - x) = (x + 1)(-10)$:

   Distribute on both sides:

   $18 - 3x = -10x - 10$

   Add $10x$ to both sides:

   $7x = 28$

   Divide both sides by $7$:

   $x = 4$

6. $2(3x + 10) = -(2 + x) - 13$:

   Distribute on both sides:

   $6x + 20 = -2 - x - 13$

   Add $x$ to both sides:

   $7x + 20 = -15$

   Subtract $20$ from both sides:

   $7x = -35$

   Divide both sides by $7$:

   $x = -5$

So, the solutions are:

1. $x = 4$
2. $x = \frac{2}{7}$
3. $x = -2$
4. $x = 5$
5. $x = 4$
6. $x = -5$