Question

Помогите решить задачу. Діти вирушили до парку розваг.Вони купили 12 квитків на колесо огляду та 9 квитків на вежу вільного падіння за однаковою ціною. Усього за квитки заплатили 2100 грн.Яка ціна квитка? Скільки гривень заплатили окремо за квитки на колесо огляду та за квитки на вежу вільного падіння?

Answer 1

Ответ:

Пошаговое объяснение:

х = цена 1 билета

Колесо обозрения = 12х грн

Башня = 9х грн

Всего = 2100 грн

12х + 9х = 2100

21х = 2100

х = 2100 : 21

х = 100

Цена 1 билета = (х) = 100 грн

Колесо обозрения = (12х) = 12 * 100 = 1200 грн

Башня = (9х) = 9 * 100 = 900 грн

1200 + 900 = 2100

Answer 2

To solve this problem, we need to find the price of each ticket and the amount paid separately for the Ferris wheel and the free fall tower.

Let's assume the price of each ticket is x.

The children bought 12 tickets for the Ferris wheel and 9 tickets for the free fall tower, and the total amount paid was 2100 UAH.

We can set up the following equation to represent the given information:

12x + 9x = 2100

Simplifying the equation:

21x = 2100

Dividing both sides of the equation by 21:

x = 100

Therefore, the price of each ticket is 100 UAH.

To find out how much was paid separately for the Ferris wheel and the free fall tower, we can multiply the price of each ticket by the number of tickets purchased for each attraction.

For the Ferris wheel: 12 tickets * 100 UAH/ticket = 1200 UAH

For the free fall tower: 9 tickets * 100 UAH/ticket = 900 UAH

So, they paid 1200 UAH for the Ferris wheel tickets and 900 UAH for the free fall tower tickets.

I hope this helps! Let me know if you have any further questions.