Question

1. Сплав состоит из серебра, меди и золота. Отношение величин равны 3:2:4 соответственно. Сколько граммов каждого металла содержится в 540 граммах сплава?

Answer 1

1) 3+2+4=9
2)540 : 9=60
3) 3*60=180(серебра)
4)2*60=120(меди)
5)4*60=240(золота)

Answer 2

Calculation of the Amount of Each Metal in the Alloy

To determine the amount of each metal (silver, copper, and gold) in the alloy, we need to calculate the grams of each metal based on the given ratio.

The ratio of the metals in the alloy is 3:2:4, respectively. This means that for every 3 parts of silver, there are 2 parts of copper and 4 parts of gold.

Let's calculate the grams of each metal in the alloy:

1. Silver: - The total ratio of the alloy is 3 + 2 + 4 = 9 parts. - To find the grams of silver in the alloy, we divide the total weight of the alloy (540 grams) by the total ratio (9 parts) and multiply it by the ratio of silver (3 parts): - Silver = (540 grams / 9) * 3 = 180 grams.

2. Copper: - To find the grams of copper in the alloy, we divide the total weight of the alloy (540 grams) by the total ratio (9 parts) and multiply it by the ratio of copper (2 parts): - Copper = (540 grams / 9) * 2 = 120 grams.

3. Gold: - To find the grams of gold in the alloy, we divide the total weight of the alloy (540 grams) by the total ratio (9 parts) and multiply it by the ratio of gold (4 parts): - Gold = (540 grams / 9) * 4 = 240 grams.

Therefore, in 540 grams of the alloy consisting of silver, copper, and gold in the ratio of 3:2:4, there are: - 180 grams of silver, - 120 grams of copper, and - 240 grams of gold.

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