Question

3•2(целых) 1/4=? 25•2(целых)2/5=?9•1(целая)3/4=?6•2(целых) 1/3=?7•3(целых)1/4=?4•2(целых)1/3=?2•4(целых)7/15=?7•3(целых)2/20=?5•2(целых)8/15=?4•4(целых)1/12=?6•2(целых)2/9=?(помогите решить дроби )​

Answer 1

Ответ:

Решение и ответ на фото)))

Answer 2

Давайте решим каждое из уравнений по порядку:

1. \(3 \cdot 2 + \frac{1}{4} = 6 + \frac{1}{4} = \frac{24}{4} + \frac{1}{4} = \frac{25}{4}\)

2. \(25 \cdot 2 \cdot \frac{2}{5} = 50 \cdot \frac{2}{5} = \frac{100}{5} = 20\)

3. \(9 \cdot 1 + \frac{3}{4} = 9 + \frac{3}{4} = \frac{36}{4} + \frac{3}{4} = \frac{39}{4}\)

4. \(6 \cdot 2 + \frac{1}{3} = 12 + \frac{1}{3} = \frac{36}{3} + \frac{1}{3} = \frac{37}{3}\)

5. \(7 \cdot 3 + \frac{1}{4} = 21 + \frac{1}{4} = \frac{84}{4} + \frac{1}{4} = \frac{85}{4}\)

6. \(4 \cdot 2 + \frac{1}{3} = 8 + \frac{1}{3} = \frac{24}{3} + \frac{1}{3} = \frac{25}{3}\)

7. \(2 \cdot 4 + \frac{7}{15} = 8 + \frac{7}{15} = \frac{120}{15} + \frac{7}{15} = \frac{127}{15}\)

8. \(7 \cdot 3 \cdot \frac{2}{20} = 21 \cdot \frac{2}{20} = \frac{42}{20} = \frac{21}{10}\)

9. \(5 \cdot 2 \cdot \frac{8}{15} = 10 \cdot \frac{8}{15} = \frac{80}{15} = \frac{16}{3}\)

10. \(4 \cdot 4 \cdot \frac{1}{12} = 16 \cdot \frac{1}{12} = \frac{16}{12} = \frac{4}{3}\)

11. \(6 \cdot 2 \cdot \frac{2}{9} = 12 \cdot \frac{2}{9} = \frac{24}{9} = \frac{8}{3}\)

Таким образом, решения уравнений:

1. \(3 \cdot 2 + \frac{1}{4} = \frac{25}{4}\) 2. \(25 \cdot 2 \cdot \frac{2}{5} = 20\) 3. \(9 \cdot 1 + \frac{3}{4} = \frac{39}{4}\) 4. \(6 \cdot 2 + \frac{1}{3} = \frac{37}{3}\) 5. \(7 \cdot 3 + \frac{1}{4} = \frac{85}{4}\) 6. \(4 \cdot 2 + \frac{1}{3} = \frac{25}{3}\) 7. \(2 \cdot 4 + \frac{7}{15} = \frac{127}{15}\) 8. \(7 \cdot 3 \cdot \frac{2}{20} = \frac{21}{10}\) 9. \(5 \cdot 2 \cdot \frac{8}{15} = \frac{16}{3}\) 10. \(4 \cdot 4 \cdot \frac{1}{12} = \frac{4}{3}\) 11. \(6 \cdot 2 \cdot \frac{2}{9} = \frac{8}{3}\)