Question

1)6/7•x=1;2) y•11/16=1;3)y•32/35=1 ПЖ срочно​

Answer 1

$\displaystyle 1)\frac{6}{7}x=1\\\\ \frac{7}{6}*\frac{6}{7}x=\frac{7}{6}*1\\\\ x=\frac{7}{6}=1\frac{1}{6}\\\\ 2)y*\frac{11}{16}=1\\\\ \frac{11}{16}y=1\\\\ y=\frac{16}{11}=1\frac{5}{11}\\\\ 3)y*\frac{32}{35}=1\\\\ \frac{32}{35}y=1\\\\ y=\frac{35}{32}=1\frac{3}{32}$

Answer 2

1) To solve the equation 6/7 * x = 1, we need to isolate the variable x. We can do this by multiplying both sides of the equation by the reciprocal of 6/7, which is 7/6. This gives us:

(6/7 * x) * (7/6) = 1 * (7/6) x = 7/6

Therefore, the solution to the equation 6/7 * x = 1 is x = 7/6. [[1]]

2) To solve the equation y * 11/16 = 1, we can isolate the variable y by multiplying both sides of the equation by the reciprocal of 11/16, which is 16/11. This gives us:

(y * 11/16) * (16/11) = 1 * (16/11) y = 16/11

So, the solution to the equation y * 11/16 = 1 is y = 16/11. [[2]]

3) To solve the equation y * 32/35 = 1, we can isolate the variable y by multiplying both sides of the equation by the reciprocal of 32/35,