Question

Arccos (-1) -arccos 1/2+3 arccos(-√3/2) Умоляю!

Answer 1

arccos (-1) -arccos 1/2+3 arccos(-√3/2)=$\pi -\frac{\pi }{3}+3*\frac{5\pi }{6}=\pi-\frac{\pi }{3}+\frac{5\pi }{2}=\frac{19\pi }{6}$ или 570°

Answer 2

Arccos(-1) - Arccos(1/2) + 3 * Arccos(-√3/2)

To solve the expression Arccos(-1) - Arccos(1/2) + 3 * Arccos(-√3/2), we can start by finding the values of the individual arccosine functions and then performing the arithmetic operations.

1. Arccos(-1): The arccosine function returns the angle whose cosine is the given number. In this case, arccos(-1) is equal to π. This is because the cosine of π is -1.

2. Arccos(1/2): The arccosine of 1/2 is π/3. This is because the cosine of π/3 is 1/2.

3. 3 * Arccos(-√3/2): The arccosine of -√3/2 is 5π/6. This is because the cosine of 5π/6 is -√3/2.

Now, we can substitute these values into the original expression:

Arccos(-1) - Arccos(1/2) + 3 * Arccos(-√3/2) = π - π/3 + 3 * (5π/6) = π - π/3 + 5π = 6π - π/3

So, the value of the expression Arccos(-1) - Arccos(1/2) + 3 * Arccos(-√3/2) is 6π - π/3.