Question

1 5/6: 3/8 + (1/6 + 3/10) × 3 Помогите

Answer 1

$1\frac{5}{6}:\frac{3}{8}+(\frac{1}{6}+\frac{3}{10})\cdot3=\frac{11}{6}\cdot\frac{8}{3}+\frac{7}{15}\cdot3=\frac{11}{3}\cdot\frac{4}{3}+\frac{7}{5}=\frac{44}{9}+\frac{7}{5}=\frac{283}{45}=6,28$

Answer 2

Calculation:

To solve the given expression 1 5/6 + 3/8 + (1/6 + 3/10) × 3, we can follow these steps:

1. Convert all the mixed numbers to improper fractions. 2. Perform the addition and multiplication operations according to the order of operations (PEMDAS/BODMAS).

Let's start by converting the mixed numbers to improper fractions:

1 5/6 can be written as 11/6 3/8 remains the same 1/6 remains the same 3/10 remains the same

Now, we can perform the addition and multiplication operations:

11/6 + 3/8 + (1/6 + 3/10) × 3 = (11/6 + 3/8) + (1/6 + 3/10) × 3 = (44/24 + 9/24) + (5/30 + 9/30) × 3 = (53/24) + (14/30) × 3

Next, we can simplify the expression and perform the multiplication:

= 53/24 + 14/10 × 3 = 53/24 + 42/10 = 53/24 + 21/5 = (53/24) + (105/24) = 158/24 = 6 10/24 = 6 5/12

So, the result of the given expression 1 5/6 + 3/8 + (1/6 + 3/10) × 3 is 6 5/12.