Question

1) |3-x|=52) |6-5x|=03) |x+5|-2=7помогитеееее пожалуйстаааааа​

Answer 1

Ответ:

1) |х-1,5|=4

x₁ - 1,5 = 4, x₂ - 1,5 = -4

x₁ = 5,5, x₂ = -2,5

2) |3-х|=5

3-x₁ = 5, 3-x₂ = -5

x₁ = -2, x₂ = 8

3) |2х-3|=0

2x-3 = 0

x = 3/2 = 1,5

4) |6-5х|=0

6-5x = 0

x = 6/5 = 1,2

5) |х+1|+5=3

|x+1| = -2 - нет решений т.к. модуль числа не отрицателен

6) |х+5|-2=7

x₁+5 = 9, x₂ + 5 = -9

x₁ = 4, x₂ = -14

Пошаговое объяснение:

Answer 2

Ответ:

1) |3-x|=5

  3-x=5

  3-x=-5

 x1=-2

  x2=8

2) |6-5x|=0

   6-5x=0

   -5x=-6

   x=$1\frac{1}{5}$

3) |x+5|-2=7

   Ix+5I=9

   

   x+5=9

   x+5=-9

   x2=4

   x1=-14

Answer 3

Solving Absolute Value Equations

To solve absolute value equations, we need to consider both the positive and negative cases for the expressions within the absolute value bars.

1) |3-x| = 5 To solve this equation, we consider two cases: - Case 1: 3 - x = 5 - Solving for x, we get: x = -2 - Case 2: 3 - x = -5 - Solving for x, we get: x = 8

Therefore, the solutions for this equation are x = -2 and x = 8.

2) |6-5x| = 0

In this case, the absolute value expression equals 0, which means the expression inside the absolute value bars must also be 0. - Setting 6 - 5x = 0 and solving for x, we get: x = 6/5

Therefore, the solution for this equation is x = 6/5.

3) |x+5| - 2 = 7

To solve this equation, we first isolate the absolute value expression: - |x + 5| = 7 + 2 - |x + 5| = 9

Now, we consider two cases: - Case 1: x + 5 = 9 - Solving for x, we get: x = 4 - Case 2: x + 5 = -9 - Solving for x, we get: x = -14

Therefore, the solutions for this equation are x = 4 and x = -14.

In summary, the solutions for the given absolute value equations are: 1) x = -2, x = 8 2) x = 6/5 3) x = 4, x = -14