Question

В первом вагоне скоростного поезда Москвы-Питер ехали 52 пассажира, что на 14 пассажиров больше, чем во втором вагоне.Сколько всего пассажиров было в первом и втором вагонах?

Answer 1

Ответ:

90 пассажиров

Пошаговое объяснение:

Первый вагон: 52

Второй вагон: на 14 меньше

Решение: Из 52 вычитаем 14. Получаем 38. Дальше К 52 прибавляем 38. Получаем 90.

Answer 2

Відповідь:

88 пасажирів в обох вагонах.

Покрокове пояснення:

1)52-14=36пасажирів у другому вагоні .

2)52+36=88пасажирів у двух вагонах.

Answer 3

Calculating the Total Passengers in the First and Second Train Cars

To calculate the total number of passengers in the first and second train cars, we can use the information provided in the question.

Let's denote the number of passengers in the first train car as x and the number of passengers in the second train car as y.

Given: - The number of passengers in the first train car is 52, which is 14 more than the number of passengers in the second train car.

We can set up the following equation based on the given information: x = y + 14.

To find the total number of passengers in both train cars, we can sum the passengers in the first and second train cars: Total passengers = x + y.

Calculating the Total Passengers

Using the equation x = y + 14, we can substitute the value of x in the equation for the total passengers: Total passengers = (y + 14) + y.

Solving for y: Total passengers = 2y + 14.

Given that the number of passengers in the first train car is 52, we can substitute this value into the equation x = y + 14: 52 = y + 14.

Solving for y: y = 52 - 14, y = 38.

Now, we can find the total number of passengers: Total passengers = 2(38) + 14, Total passengers = 76 + 14, Total passengers = 90.

Answer

Therefore, there were 52 passengers in the first train car and 38 passengers in the second train car, making a total of 90 passengers in both train cars.